Web18 mei 2024 · Answer:x + y = a + 2b + c ÷ 2Step-by-step explanation: a + b ÷ 2 = x b + c ÷ 2 = y a + b = 2x 1 + b = 2x1b + c = 2y 2 + b = 2x 1b + c = 2y21 + 2 + b = 2x1b + c = 2y 21 … WebSquaring this equation we have $a^2 = b^2 + (2bk + k^2)$ but $2bk + k^2$ is just another positive so $a^2 > b^2$. The reason we know $2bk + k^2$ is positive is because of the …
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Web30 mrt. 2024 · It is given that a, b, c are in AP So, their common difference is same b a = c b b + b = c + a 2b = c + a b = ( + )/2 Also given that b, c, d are in GP So, their common … WebIf a,b,c are in A.P. in a2,b2,c2 are in H.P., then 2247 81 Sequences and Series Report Error A a = b = c B 2b = 3a+c C b2 = 8ac D none of these Solution: Since a,b,c are in A.P. ∴ b −a = c −b ...(1) Since a2,b2,c2 are in H.P. ∴ b21 − a21 = c21 − b21 ⇒ a2b2a2−b2 = b2c2b2−c2 ⇒ a2(a−b)(a+b) = c2(b−c)(b+c) ⇒ a2a+b = c2b+c [Using (1)]
Web27 jul. 2024 · a , b and c are in AP then we have to find the value of (a - c)²/ (b² - ac). solution : given a , b and c are in Arithmetic progression. so the common difference must be same. i.e., (b - a) = (c - b) ⇒b = (a + c)/2 ....... (1) now (a - c)²/ (b² - ac) = (a - c)²/ [ (a + c)²/4 - ac] [ from eq (1). ] = [4 (a - c)²]/ [ (a + c)² - 4ac] Web28 aug. 2024 · Click here 👆 to get an answer to your question ️ if a,b,c are in AP then a/bc, 1/c, 2/b are in
Web28 mrt. 2024 · a, b, c are in AP => 2b = a + c (1) b, c, d are in GP => c² = bd (2) c, d, e are in HP or 1/c, 1/d, 1/e are in HP => 2/d = 1/c + 1/e (3) We have to prove that a, c, e are in GP or, in mathematical terms, c² = ae. We'd first solve by the simple, straight forward approach which is commonly the easiest to think of.
WebIf a,b,c are in A.P., and a 2,b 2,c 2 are in H.P., then- This question has multiple correct options A a=b=c B a 2=b 2= 2c 2 C a,b,c are in G.P. D 2−a,b,c are in G.P. Hard … pu polish asian paintsWebSolution Given a, b, c are in GP So b 2 = a c.. ( i) a ( b 2 + c 2) = a ( a c + c 2) = a ( a c) + a c 2 = a 2 c + a c = c ( a 2 + b 2) a ( b 2 + c 2) = c ( a 2 + b 2) Hence, the value of a ( b 2 + c 2) i s c ( a 2 + b 2) Suggest Corrections 2 Similar questions Q. If a, b, c are in G.P., prove that: (i) a (b 2 + c 2) = c (a 2 + b 2) pu platten isolierungWeb29 mrt. 2024 · Transcript. Ex 7.2, 8 If A and B are (– 2, – 2) and (2, – 4), respectively, find the coordinates of P such that AP = 3/7 AB & P lies on the line segment AB. Let the co−ordinates of point P be P (x, y) It is given that AP = 3/7 (AB) AP = 3/7 (AP + PB) 7AP = 3AP + 3PB 7AP − 3AP = 3PB 4AP = 3PB 𝐴𝑃/𝑃𝐵 = 3/4 Hence the point P ... pu polish kaise hota haiWeb16 jan. 2024 · If α α, β β, γ γ are roots of the equation x2(px + q) = r(x + 1) x 2 ( p x + q) = r ( x + 1), then the value of determinant ` {: (1+alpha,1,1), (1, 1+beta,1), (1,1,1+gamma asked Oct 4, 2024 in Determinants by VaibhavNagar (93.4k points) pu polymerisationWeb9 apr. 2024 · Busch, who'll try and make it two in a row on the dirt at Bristol Motor Speedway on Sunday, acknowledged that NASCAR's rules process is front-and-center these days of punishment and appeals. Last ... pu pillowWeb30 mrt. 2024 · If a, b, c, are in A.P., then the determinant 8 (x+2&x+3& x+2a@x +3&x+4& x+2b@x +4&x+5&x+2c) is A. 0 B. 1 C. x D. 2x Since a, b & c are in A.P Then a – b = c … pu qualitätWebSince, a, b, c are in Arithmetic Progression 1 - a, 1 - b, 1 - c are in Arithmetic Progression. Then, 1 1 - a, 1 1 - b, 1 1 - c are in Harmonic Progression. So, x, y, z are in Harmonic Progression. Hence, correct option is ( C) Suggest Corrections 3 Similar questions Q. Let a,b and c be in AP and a <1, b <1 c <1. If x=1+a+a2+...... ∞ pu rakila kotarov vuka